This does not necessarily mean the entirety of the malic acid underwent the dehydration reaction to form fumaric/maleic acid. We are told dehydration of malic acid results in the formation of fumaric acid and its cis isomer, maleic acid. All of the malic acid underwent the dehydration reaction to form fumaric/maleic acid.An increased temperature helps the reaction move forward and that temperature is not necessarily the temperature at which aspartic acid is stable. This is not an assumption that has to be made for aspartic acid to be formed by the prebiological synthesis in the passage. Aspartic acid is unstable at temperatures below 150☌.Given this information, we have to decide what assumptions are being made if scientists conclude that aspartic acid was formed by the prebiological synthesis in the passage. The author then tells us ammonia reacted with fumaric, maleic, and malic acids to afford a prebiological synthesis of aspartic acid. We can stick with answer choice A as our best answer.Ģ) The author goes through Scheme I in the passage to explain the formation of malic acid and subsequently fumaric/maleic acid. The most polar nonpolar molecules will still travel furthest. We expect thickness of paper is not going to affect the relative migration of individual components in the sample. This answer choice is similar to answer choice C. That migration still depends on affinities. Stationary phase concentration is not going to affect the relative migration of individual components in the sample. This is going to be similar to answer choice B. The most polar nonpolar molecules will travel furthest. The migration is dependent on affinities and hydrogen bonding. Solute concentration does not change the migration of individual components in the sample. Nonpolar molecules will not be attracted to the water molecules attached to the cellulose and will travel further along the paper, while polar molecules will have a high attraction for the molecules and not travel as far Hydrogen bonding to the stationary phase will determine the migration of individual components in the sample. Nonpolar molecules will not be attracted to the water molecules attached to the cellulose and will travel further along the paper, while polar molecules will have a high attraction for the molecules and not travel as far. We’re told in our question stem, water absorbed on cellulose (a very polar compound) functions as the stationary phase. The higher the adsorption to the stationary phase, the slower the molecule will move through the column. All chromatography works by having a mobile phase (the part that moves), and a stationary phase (the part that stays still) which allow for separation of the different fractions of the original mixture. Chromatography is a separation technique that takes advantage of the different products’ solubilities and relative affinities for the stationary phase used. To answer this question, we can do a quick overview of chromatography, then we’ll identify the principal factor determining the migration of individual components in the sample. 1) Despite being a passage-based question, we should be able to answer this question using external knowledge.
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